Answer to Question #2797 in Mechanics | Relativity for muskan
1.) v = u+at
2.)v2 = u2+2as
3.)s = ut+1/2at2
∫v0 dt = v0 t + x0 = x(t)
where x0 is the initial position.
If body has nonzero acceleration than
where a is the acceleration.
If x0=0 we get formula 3.
at2/2 + v0 t = x(t) - x0 = x(t) = S.
Differentiating this expression we get
x' (t) = v0+at = v(t)
And that is formula 1.
v = v0+at
S = v0 t+(at2)/2
t = (v-v0)/a
S=v0 (v-v0)/a+(a(v2-2v2 v02 + v02))/(2a2 ) = (v2-v02)/2a
This is formula 2.
This graph illustrate function
This graph illustrates function
at2/2 + v0t + x0 = x(t)
Area under the line for given interval of t gives S.
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