Prove graphically and anatically following equations of motions;
1.) v = u+at
2.)v[sup]2[/sup] = u[sup]2[/sup]+2as
3.)s = ut+1/2at[sup]2[/sup]
1
Expert's answer
2011-06-15T11:44:44-0400
Let x(t) be the position of some body. Let v(t) be the velocity of some body. Than its position at any moment of the time will be ∫v0 dt = v0 t + x0 = x(t) where x0 is the initial position. If body has nonzero acceleration than at2/2+v0 t+x0=x(t) where a is the acceleration. If x0=0 we get formula 3. at2/2 + v0 t = x(t) - x0 = x(t) = S. Differentiating this expression we get x' (t) = v0+at = v(t) And that is formula 1. v = v0+at S = v0 t+(at2)/2 t = (v-v0)/a S=v0 (v-v0)/a+(a(v2-2v2 v02 + v02))/(2a2 ) = (v2-v02)/2a
a=(v2-v02)/2S v2=v02+2Sa.
This is formula 2.
This graph illustrate function v0t+x0=x(t).
This graph illustrates function at2/2 + v0t + x0 = x(t) Area under the line for given interval of t gives S.
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