A projectile is fired from the ground with an initial velocity of 82 m/s at an angle of 55 above the horizontial .
1- What are the initial x and y componets of the velocity ?
2- What is the x component of the projectile 1.2 s after being fired , relative the firing point?
3- What is the y component of the projectile 1.2 s after being fired , relative the firing point ?
1) Let Vx and Vy be the component s of the velocity. Then their initial values are the following: Vx(0)= 82*cos55 =47.03 Vy(0)= 82*sin 55=67.17
2) The move of projectile consists of two moves: along x-axis and along y-axis. On the projectile act a gravitation force along y-axis. Therefore along x-axis projectile moves with constant velocity& Vx(0), whence the x component of projectile after 1.2& s is equal to Sx = Vx * t = 82*cos55 * 1.2 = 47.03*1.2 = 56.44
3) The move of projectile along y-axis has constant acceleration g = -9.8 m/s^2, since it is directed down, while Vy is directed up. Hence y component of projectile after 1.2& s is equal to Sx = Vx * t – g t^2 /2 = & 82*sin55 * 1.2 – 9.8 (1.2)^2 / 2 = 67.17 *1.2 – 7.056 = 73.548