A 75 kg box slides down a 25.0 degrees ramp with an acceleration of 3.60 m/s/s.find the coefficient of kinetic friction between the box and ramp
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Expert's answer
2012-11-16T05:17:28-0500
First, you need to find the Force that will impede the moving
Force = Mass * Acceleration Force = 75kg * 3.60m/s squared Force = 270 N
Second, find the parallel force ( the force in which it goes up and down )
F(parallel) = Weight * sin(Theta) Weight = mass * gravity ( you should know this formula by now )
Weight = 75 kg * 9.81 m/ssquared (coef of gravity ) Weight = 735 N
F(parallel) = 735 N * sin(25) F(parallel) = 310.9 N
Third, you need to find the force due to friction ( the stopping force )
Force of Friction = F(parallel ) - force Force of friction = 310.9N - 270 N Force of friction = 41 N
Now, you should use the formula to find the coefficient ( Force of Friction = coef * normal )
To find normal, you need to remember that if the object is moving in an angle, thennormal force = weight * cos 25, if it is moving horizontally, normal force = weight )
So since this is moving in an able,
Normal Force = 735 N * cos(25) Normal Force = 667N
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Thank you so much !! I totally get it now!!
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