Answer to Question #18852 in Mechanics | Relativity for Lissah
Force = Mass * Acceleration
Force = 75kg * 3.60m/s squared
Force = 270 N
Second, find the parallel force ( the force in which it goes up and down )
F(parallel) = Weight * sin(Theta)
Weight = mass * gravity ( you should know this formula by now )
Weight = 75 kg * 9.81 m/ssquared (coef of gravity )
Weight = 735 N
F(parallel) = 735 N * sin(25)
F(parallel) = 310.9 N
Third, you need to find the force due to friction ( the stopping force )
Force of Friction = F(parallel ) - force
Force of friction = 310.9N - 270 N
Force of friction = 41 N
Now, you should use the formula to find the coefficient ( Force of Friction = coef * normal )
To find normal, you need to remember that if the object is moving in an angle, thennormal force = weight * cos 25, if it is moving horizontally, normal force = weight )
So since this is moving in an able,
Normal Force = 735 N * cos(25)
Normal Force = 667N
41 N = Coef * 667N
Coef = 0.061
1 year ago
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