Question #18845

An engineer weighs a sample of mercury (p=13.6 x 10^3 kg/m^3) and finds that the weight of the sample is 4.6 N.
What is the sample's volume? The acceleration of gravity is 9.81 m/s^2.
Answer is units of m^3.

Expert's answer

The mass of the sample is

m = 4.6[N]/9.81[m/s²].

So, it's volume is

V = m/p = 4.6[N]/9.81[m/s²]/13.6*10³[kg/m³] ≈ 3.44786*10^(-5)[m³].

m = 4.6[N]/9.81[m/s²].

So, it's volume is

V = m/p = 4.6[N]/9.81[m/s²]/13.6*10³[kg/m³] ≈ 3.44786*10^(-5)[m³].

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