Answer to Question #16241 in Mechanics | Relativity for Colby
a = F/m,
with F just the force of friction Ff. But
Ff = Fn*u,
where Fn is the normal force:
Fn = m*g.
a = Fn*u/m = m*g*u/m,
and you don't need to know m, as
a = u*g.
0 = 16[m²/s²] + 2*u*g*d
==> d = -16[m²/s²]/(2*(-9.8)[m/s²] * 0.2)
==> d ~ 4.1 [m].
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