Answer to Question #16241 in Mechanics | Relativity for Colby

Question #16241
A box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is 0.20 and the push imparts an initial speed of 4.0 m/s. I know the answer I just am lost as to how to solve it
1
Expert's answer
2012-10-12T08:45:17-0400
We have that

a = F/m,

with F just the force of friction Ff. But

Ff = Fn*u,

where Fn is the normal force:

Fn = m*g.

Therefore,

a = Fn*u/m = m*g*u/m,

and you don't need to know m, as

a = u*g.

We have

0 = 16[m²/s²] + 2*u*g*d
==> d = -16[m²/s²]/(2*(-9.8)[m/s²] * 0.2)
==> d ~ 4.1 [m].

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS
paypal