Question #16026

A daredevil jumps a canyon 14 m wide. To do so, he drives a car up a 19° incline. What minimum speed must he achieve to clear the canyon? If the daredevil jumps at this minimum speed, what will his speed be when he reaches the other side?

Expert's answer

g*(t/2)=V0y=V0sin19 (That means, that after half of time we will reach maximum height

So, t=2V0sin19/g

S=Vox*t

V0x=v0*cos19

S=V0cos19*2v0sin19/g

S=(V0^2)sin38/g

V0=Sqrt(Sg/sin38)

V0=Sqrt(140/sin38)

So, t=2V0sin19/g

S=Vox*t

V0x=v0*cos19

S=V0cos19*2v0sin19/g

S=(V0^2)sin38/g

V0=Sqrt(Sg/sin38)

V0=Sqrt(140/sin38)

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