Question #15981

a ball is thrown upward with an initial velocity of 14m/s. using the approximate value of g=10m/s^2, what are the magnitude and direction of the balls velocity.
a) 1 second after it is thrown
b) 2 second after it is thrown

Expert's answer

The equation for velocity is

v=v0 - gt

where v0=14m/s, g=10m/s^2.

in 1 second:

v=14-10=4m/s

it is positive so direction is upwards

in 2 seconds:

v=14-20=-6m/s

it is negative so direction is downwards

v=v0 - gt

where v0=14m/s, g=10m/s^2.

in 1 second:

v=14-10=4m/s

it is positive so direction is upwards

in 2 seconds:

v=14-20=-6m/s

it is negative so direction is downwards

## Comments

## Leave a comment