# Answer on Mechanics | Relativity Question for bri

Question #14629

A 1 kg poodle running right at 3 m/s has an elastic head on collision with a 9 kg basset hound walking left with a velocity of 1 m/s. After the collision the poodle bounces off to the left at 3 m/s. Whats the basset hounds velocity after the collision?

Expert's answer

Let m1 is the poodle's weight and V1 is its velocity, m2 is the

basset

hound's weight and V2 is its velocity before the collision.

m1 * V1

- m2 * V2 = - m1 * V1' + m2 * V2'

V2' = (m1 * V1 - m2 * V2 + m1 * V1') /

m2

V2' = (1 * 3 - 9 * 1 + 1 * 3) / 9 = - 1/3 m/s

Answer: 1/3 m/s (directed

to the left).

basset

hound's weight and V2 is its velocity before the collision.

m1 * V1

- m2 * V2 = - m1 * V1' + m2 * V2'

V2' = (m1 * V1 - m2 * V2 + m1 * V1') /

m2

V2' = (1 * 3 - 9 * 1 + 1 * 3) / 9 = - 1/3 m/s

Answer: 1/3 m/s (directed

to the left).

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