Answer to Question #14597 in Mechanics | Relativity for Jayflord Banac
1. What is the average power of the elevator motor during this period?
2. How does this power compare with the motor when the elevator moves at its cruising speed?
650 kg, t = 3 s, V0 = 0, V = 1.75 m/s.
V = V0 + a * t
a = V / t
F = m *
(g + a) = 650 * ( 9.81 + 0.58) = 6747N
The distance the elevator travels in 3
seconds is D =a * t^2 / 2 =
0.583 * 3^2 / 2 = 2.62 m
P = F * D / t =
2. How does this power compare with the motor when the elevator
at its cruising speed:
P = F * V = 6370N x 1.75m/s = 11,147.5 W
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Dear Bhavya mohta,
please use panel for submitting new questions
By doing it with power =work done/time taken I am getting a different answer .
Please help me with it