# Answer to Question #1434 in Mechanics | Relativity for Connie

Question #1434

A harmonic wave is traveling along a rope. It is observed that the oscillator that generates

the wave completes 40.2 vibrations in 33.7 s. Also, a given maximum travels 438 cm alongthe rope in 11.7 s.<br>

What is the wavelength?<br>

Answer in units of cm.

the wave completes 40.2 vibrations in 33.7 s. Also, a given maximum travels 438 cm alongthe rope in 11.7 s.<br>

What is the wavelength?<br>

Answer in units of cm.

Expert's answer

The frequency of the wave is

f = 40.2/33.7 = 1.193 1/s.

The speed of the wave -

v = 0.438/11.7 = 0.037 m/s

The wavelength would be equal to

λ = v/f = 0.037 [m/s]/1.193 [1/s] = 0.031 m = 3 cm.

f = 40.2/33.7 = 1.193 1/s.

The speed of the wave -

v = 0.438/11.7 = 0.037 m/s

The wavelength would be equal to

λ = v/f = 0.037 [m/s]/1.193 [1/s] = 0.031 m = 3 cm.

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