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Answer to Question #1434 in Mechanics | Relativity for Connie

Question #1434
A harmonic wave is traveling along a rope. It is observed that the oscillator that generates
the wave completes 40.2 vibrations in 33.7 s. Also, a given maximum travels 438 cm alongthe rope in 11.7 s.<br>
What is the wavelength?<br>
Answer in units of cm.
Expert's answer

The frequency of the wave is f = 40.2/33.7 = 1.193 1/s. The speed of the wave - v = 4.38/11.7 = 0.37 m/s The wavelength would be equal to λ = v/f = 0.37 [m/s]/1.193 [1/s] = 0.31 m = 31 cm.

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Comments

Assignment Expert
30.07.19, 15:49

Dear Tyosongu James u, thank you for the comment

Tyosongu James u
29.07.19, 17:52

How is the distance =0.438

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