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Answer to Question #1434 in Mechanics | Relativity for Connie

Question #1434
A harmonic wave is traveling along a rope. It is observed that the oscillator that generates
the wave completes 40.2 vibrations in 33.7 s. Also, a given maximum travels 438 cm alongthe rope in 11.7 s.<br>
What is the wavelength?<br>
Answer in units of cm.
Expert's answer
The frequency of the wave is
f = 40.2/33.7 = 1.193 1/s.
The speed of the wave -
v = 0.438/11.7 = 0.037 m/s
The wavelength would be equal to
&lambda; = v/f = 0.037 [m/s]/1.193 [1/s] = 0.031 m = 3 cm.

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