# Answer to Question #1432 in Mechanics | Relativity for ddddd

Question #1432

Average speed equals distance divided by time. On a journey to the Alpha Centauri star system, a space probe travels a distance of 4.12×10

^{16}meters in 1.73×10^{10}seconds. (a) Find its average speed in meters per second. (b) How long did the journey take in years? Use 365.24 days per yearExpert's answer

a) V = S/t = 4.12×10

b) In the year there is 365.24 days, in the day there is 24 hours, in one hour - 60 minutes, in one minute - 60 seconds; thus

1.73*10

^{16}[m] / 1.73×10^{10}[s] = 2381502.89 m/sb) In the year there is 365.24 days, in the day there is 24 hours, in one hour - 60 minutes, in one minute - 60 seconds; thus

1.73*10

^{10}/(365.24*24*60*60) = 548.22 years.Need a fast expert's response?

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