Question #119197

a boomerang is thrown with the following displacements: 4.5-m to the east, 7.5-m 30° north of west, and 3.0-m 10° south of west. what is the resulatant displacement?

Expert's answer

"\\sum{x} \\to 4.5-7.5\\cdot \\cos 30\u00b0+3\\cdot \\cos40\u00b0=0.303 m"

"\\sum{y} \\to 7.5\\cdot \\sin 30\u00b0-3\\cdot \\sin40\u00b0=1.82 m"

"Displacement =\\sqrt{0.303^2+1.82^2}=1.85m"

"\\overrightarrow{r}=0.303\\overrightarrow{i}+1.82\\overrightarrow{j}"

Learn more about our help with Assignments: MechanicsRelativity

## Comments

## Leave a comment