Question #104835

An elastic collision takes place between a 0.090-kg

toy car moving at 10 ×10^2 m/h and a 0.014-kg toy car moving at 20 *10^9 mm/yr

Part A

What is the kinetic energy of the system?

toy car moving at 10 ×10^2 m/h and a 0.014-kg toy car moving at 20 *10^9 mm/yr

Part A

What is the kinetic energy of the system?

Expert's answer

Just add their kinetic energies! But don't forget to convert the units:

"10\\cdot10^2" m/h is "10\\cdot10^2\/3600=0.28\\text{ m\/s}."

Now "20\\cdot10^9" mm/yr. 1 meter has 1000 millimeters, 1 year is 365 days long each 24 hours long each 3600 seconds long:

The kinetic energy of a body is

The kinetic energy of our system is

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