# Answer to Question #104549 in Mechanics | Relativity for havefun7741

https://upload.cc/i1/2020/03/03/UFc9i5.jpg

d8 is 4

1
2020-03-06T10:27:55-0500

i)

"u=\\frac{d}{T}=\\frac{40+80+60}{5+4+3}=15\\frac{m}{s}"

ii)

"\\bold{s}=(40\\cos{30}\\bold{i}-40\\sin{30}\\bold{j})+80\\bold{i}+\\\\+(60\\cos{50}\\bold{i}+60\\sin{50}\\bold{j})"

"\\bold{s}=(153\\bold{i}+26\\bold{j})\\ m"

iii)

"\\bold{v}=\\frac{(153\\bold{i}+26\\bold{j})}{5+4+3}=(12.8\\bold{i}+2.2\\bold{j})\\frac{m}{s}"

iv)

"v=\\sqrt{12.8^2+2.2^2}=12.9\\frac{m}{s}"

"\\theta=\\arctan{\\frac{2.2}{12.8}}=9.6\\degree"

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