Question #103455

an helicopter hoovers clear on the ground issuing slip diameter 20 meters at speed of 20 m/s. Determine the mass flow rate of the air passing through the rotor and the mass of the helicopter?

Expert's answer

As per the question,

It is given that the diameter of the slip =20m

So, the radius of the slip =diameter/2=10m

Speed =20m/sec

The density of the air"=1.225 kg\/m^3"

So, mass flow rate = area covered by the slip x velocity of the slip

"=\\pi r^2\\times v=\\dfrac{22\\times 10\\times 10\\times 20}{7}=6.285\\times10^3m^3\/sec"

We know that mass of the helicopter= density of the air x flow rate

="6.285\\times1.225\\times 10^3=7.699\\times10^3 kg=7699kg"

Learn more about our help with Assignments: MechanicsRelativity

## Comments

## Leave a comment