Answer to Question #103414 in Mechanics | Relativity for Bryan Torres

Mechanics | Relativity

Question #103414

A projectile's launch speed is 6.70 times its speed at maximum height. Find the launch angle θ0.

Expert's answer

The velocity of the projectile at maximum height

v=v_0\cos\theta.

Hence

v_0=6.70v=6.70v_0\cos\theta.

\cos\theta=1/6.70=0.149,

\theta=81.4^{\circ}

Learn more about our help with Assignments: Mechanics Relativity

Comments

No comments. Be the first!

Leave a comment

Related Questions

1. The gravitational force acting on the satellite is always directed towards the centre of Earth does
2. You and your friend are running in a long racetrack. You pass the starting line at a constant 4 mete
3. A centrifuge in the shape of a uniform cylinder of radius 20 cm and mass 10 kg cylinder is spinning
4. A typical mountaineer rope about 35cm long will give a distance of about 1.6m under the weight of a
5. Two objects are connected by a light string that passes over a frictionless pulley. The coefficient
6. A bullet of mass 55g is shot through a watermelon with mass 1.2kg. the watermelon flies back at 1.5m
7. Two rollerbladers face each other and stand at rest on a flat parking lot. Tony has a mass of 65kg,