Question #1028

A car with mass 910 kg passes over a bump

in a road that follows the arc of a circle of

radius 37.5 m as shown in the figure.

The acceleration of gravity is 9.8 m/s2 .What is the maximum speed the car can

have as it passes the highest point of the

bump before losing contact with the road?

Answer in units of m/s.

car is 910kg

in a road that follows the arc of a circle of

radius 37.5 m as shown in the figure.

The acceleration of gravity is 9.8 m/s2 .What is the maximum speed the car can

have as it passes the highest point of the

bump before losing contact with the road?

Answer in units of m/s.

car is 910kg

Expert's answer

We need the figure referred in the question. Most probably at the highest point, according to Newton's laws,

mg = ma_{ca}, where a_{ca} is centrifugal acceleration,

Thus g = a_{ca} = v^{2}/R, R is the radius of the arc.

v = √ gR = 19.17 m/s

mg = ma

Thus g = a

v = √ gR = 19.17 m/s

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