Answer to Question #1026 in Mechanics | Relativity for Erin
F= - kΔx = (EA0/L0)Δx = Δx
k = (E*πR2 / L0) = (3.1x106* 3.1415* (0.0934x10-2)2 / 2.69x10-2) = 315.82 N/m
E is the Young's modulus
πR2 is the original cross-sectional area through which the force is applied;
L0 is the original length of the object.
Δx = F / k = 0.0418 / 315.18 = 0.00013 m = 1.3x10-4 mA = kx2/2 = 315.18* (1.3x10-4 )2/2 = 2.66 x 10-6 J.
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