61 731
Assignments Done
97,8%
Successfully Done
In May 2018

Answer to Question #82 in Trigonometry for manank

Question #82
I don't know how to prove that:
2(sin6+cos6)-3(sin4+cos4-1)=0
Expert's answer
Try to use this formulas for your problem:
sin3x = 3sinx - 4(sin^3(x))
cos3x = 4(cos^3(x)) - 3cosx
sin2x = 2sinxcosx
cos2x = cos^2(x) - sin^2(x) = 2(cos^2(x)) - 1 = 1 - 2(sin^2(x))

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

Submit
Privacy policy Terms and Conditions