# Answer to Question #6240 in Trigonometry for joy

Question #6240

sin(x)=csc(x)

Expert's answer

sin x=1/sin x

sin

So we have sin x=1 or sin x=-1

Consider the first equation sin x=1

hence x=pi/2+2k pi where k - integer

Consider the second equation sin x=-1

hence x=-pi/2+2k pi where k - integer

Therefore the answer is x=+-pi/2+2k pi where k - inetger

sin

^{2}x=1So we have sin x=1 or sin x=-1

Consider the first equation sin x=1

hence x=pi/2+2k pi where k - integer

Consider the second equation sin x=-1

hence x=-pi/2+2k pi where k - integer

Therefore the answer is x=+-pi/2+2k pi where k - inetger

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