Answer on Trigonometry Question for Kewal
tan2A = (sec2A+1)√sec²A-1
)* sqrt( (1-cos^2(A) )/cos^2(A) )=
sin(A)/cos(A)=2*cos(A)*sin(A)/cos(2A)=sin(2A)/cos(2A)=tan( 2A) and that just we
need we use here sin^2(A)+cos^2(A)=1, sin(2A)=2*sin(A)*cos(A),
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