Question #5903

sin((theta divided by 3) + (pie divided by 4)) = one half

Expert's answer

sin((theta divided by 3) + (pie divided by 4)) = one half

theta/3

+pie/4=pie/6 +2*pie*k or theta/3 +pie/4=5*pie/6 +2*pie*k, where k is

integer

then theta/3=pie/6 -pie/4 +2*pie*k or theta/3=5*pie/6 -pie/4

+2*pie*k, where k is integer

then theta/3= -pie/12 +2*pie*k or

theta/3=7*pie/12 +2*pie*k, where k is integer

then theta= -pie/4 +6*pie*k or

theta=7*pie/4 +6*pie*k, where k is integer

theta/3

+pie/4=pie/6 +2*pie*k or theta/3 +pie/4=5*pie/6 +2*pie*k, where k is

integer

then theta/3=pie/6 -pie/4 +2*pie*k or theta/3=5*pie/6 -pie/4

+2*pie*k, where k is integer

then theta/3= -pie/12 +2*pie*k or

theta/3=7*pie/12 +2*pie*k, where k is integer

then theta= -pie/4 +6*pie*k or

theta=7*pie/4 +6*pie*k, where k is integer

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