Answer to Question #5499 in Trigonometry for cap
N(t) = A*sin(a(t+c)),
where N is the number of people and t is time in months.
Let's solve the following system of equations:
A*sin(a(0+c)) = 15000,
A*sin(a(6+c)) = 500;
Since |sin(x)| <= 1, we'll assume A = 15000.
sin(a(0+c)) = 1,
sin(a(6+c)) = 1/30;
sin(ac) = 1,
sin(6a+ac) = 1/30;
ac = pi/2,
6a+ac = arcsin(1/30);
6a+pi/2 = arcsin(1/30);
a = (arcsin(1/30)-pi/2)/6 ≈ -0.244342861570884;
c = pi/(2a) = pi/((arcsin(1/30)-pi/2)/3) = (3pi)/(arcsin(1/30)-pi/2) ≈ -6.428656506256111.
So, we've got the following model:
N(t) = 15000*sin(-0.244342861570884*(t-6.428656506256111)).
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