Answer to Question #20813 in Trigonometry for Kristen Woods

Question #20813
if f(x)=x^2+3 and g(x)=3x-1 then find the following 1d. (fg)(x) 1e. fg(-1) 1f. (f/g)(x)
1
Expert's answer
2012-12-20T09:06:06-0500

1d. (fg)(x)=(x^2+3)(3x-1)=3x^3-x^2+9x-3
1e. (fg)(-1)=3(-1)^3-(-1)^2+9(-1)-3=-3-1-9-3=-16
1f. (f/g)(x)=(x^2+3)/(3x-1)

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