Question #20812

if f(x)=x^2+3 and g(x)=3x-1
then find the following
1a. (f+g)(x)
1b. (f+g)(3)
1c. (f-g)(x)

Expert's answer

1a

(f+g)(x)=f(x)+g(x)=x^2+3+3x-1=x^2+3x+2

1.b

(f+g)(x)=x^2+3x+2

(f+g)(3)=3^2+3*3+2=9+9+2=20

1c.

(f-g)(x)= x^2+3-(3x-1)=x^2-3x+4

(f+g)(x)=f(x)+g(x)=x^2+3+3x-1=x^2+3x+2

1.b

(f+g)(x)=x^2+3x+2

(f+g)(3)=3^2+3*3+2=9+9+2=20

1c.

(f-g)(x)= x^2+3-(3x-1)=x^2-3x+4

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