# Answer to Question #20251 in Trigonometry for Kristen Woods

Question #20251

solve each quadratic in form equation

1. 4y^4+9=13y^2

1. 4y^4+9=13y^2

Expert's answer

let t=y^2 then

4t^2-13t+9=0

D=13^2-4*9*4=169-144=25

t12=(13+-5)/8 so t1=1, t2=9/4

but t=y^2

so y^2=1 or y^2=9/4

y1=1, y2=-1, y3=-3/2, y4=3/2

4t^2-13t+9=0

D=13^2-4*9*4=169-144=25

t12=(13+-5)/8 so t1=1, t2=9/4

but t=y^2

so y^2=1 or y^2=9/4

y1=1, y2=-1, y3=-3/2, y4=3/2

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