Answer to Question #20127 in Trigonometry for Jill
3x/2=pi/4+2k*pi, where k is integer,& x=pi/6+4k*pi/3
3x/2=7pi/4+2k*pi, where k is integer, x=7pi/6+4k*pi/3
Summand 2k*pi is added due to fact that cos is periodic function.
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