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Answer to Question #19399 in Trigonometry for mary
Question #19399
tan x sin x = sec x - cos x
Expert's answer
tanxsinx=secx-cosx
sin^2x/cosx=secx-cosx
sin^2x=cosxsecx-cosx^2
sin^2x+cos^2x=1
1=1
sin^2x/cosx=secx-cosx
sin^2x=cosxsecx-cosx^2
sin^2x+cos^2x=1
1=1
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#339914 on Dec 2023
#339914 on Dec 2023
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