Question #19391

i need help solving this trig identity. sin^6x = cos^6x = 1-3/4sin^22x

Expert's answer

sin^6x=cos^6x only when tg^6x=1 - x=-pi/4, pi/4

cos^6x=1-0.75sin^22x when cos^6x+0.75sin^22x=1

6>2 and 22>2, that means, that we have to get cos^6x=1- x=-pi, x=pi

cos^6x=1-0.75sin^22x when cos^6x+0.75sin^22x=1

6>2 and 22>2, that means, that we have to get cos^6x=1- x=-pi, x=pi

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