# Answer to Question #5285 in Statistics and Probability for kira

Question #5285

If my boss has 42 seats and 101 wheels, how many bikes and trikes does he have?

Expert's answer

Let the boss has X bikes and Y trikes. So,

2X + 3Y = 101 (1) - the total number of wheels;

X + Y = 42 (2) - total number of seats.

We've got the system of equations. Let's solve it.

(2) ==> X = 42 - Y;

(1): 2(42 - Y) + 3Y = 101;

84 + Y = 101;

Y = 17;

X = 42 - 17 = 25.

So, boss has 25 bikes and 17 trikes.

2X + 3Y = 101 (1) - the total number of wheels;

X + Y = 42 (2) - total number of seats.

We've got the system of equations. Let's solve it.

(2) ==> X = 42 - Y;

(1): 2(42 - Y) + 3Y = 101;

84 + Y = 101;

Y = 17;

X = 42 - 17 = 25.

So, boss has 25 bikes and 17 trikes.

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