Answer to Question #26227 in Statistics and Probability for Kayla

Question

Calculate the margin of error in estimating a population mean , using confidence interval of 95% , mean of 50 and sigma squared of 0.25

Answer 1

The margin of error in estimating a population mean equals:
m - z*sigma, m + z*sigma
m - mean
sigma - standard deviation
z - -score for the desired confidence-level probability ( for confidence interval of 95% z = 1.96 )
in our case sigma = Sqrt[0.25] = 0.5
the margin of error in estimating a population mean equals:
[50 - 1.96*0.5,& 50 + 1.96*0.5] = [49.02, 50.98 ]
Answer:& [49.02, 50.98 ]