Question #26227

Calculate the margin of error in estimating a population mean , using confidence interval of 95% , mean of 50 and sigma squared of 0.25

Expert's answer

The margin of error in estimating a population mean equals:

m - z*sigma, m + z*sigma

m - mean

sigma - standard deviation

z - -score for the desired confidence-level probability ( for confidence interval of 95% z = 1.96 )

in our case sigma = Sqrt[0.25] = 0.5

the margin of error in estimating a population mean equals:

[50 - 1.96*0.5,& 50 + 1.96*0.5] = [49.02, 50.98 ]

Answer:& [49.02, 50.98 ]

m - z*sigma, m + z*sigma

m - mean

sigma - standard deviation

z - -score for the desired confidence-level probability ( for confidence interval of 95% z = 1.96 )

in our case sigma = Sqrt[0.25] = 0.5

the margin of error in estimating a population mean equals:

[50 - 1.96*0.5,& 50 + 1.96*0.5] = [49.02, 50.98 ]

Answer:& [49.02, 50.98 ]

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