Answer to Question #10345 in Other Math for Manthan khorwal
Substituting these formulae into the left part of initial equation we obtain
x^3+3x^2y+3xy^2+y^3-(x^3-3x^2y+3xy^2-y^3)-6y(x2-y2)=|...open the braces...| =
=8y^2 so that's it
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