# Answer on Other Math Question for judson9

Question #10149

Playing texas hold'em yesterday my Sweetie had a 7 and a queen in the pocket. On the board came up three sevens and two queens. Not a very likely mix. What is the likelihood of such a thing?

Thanks, Jerry

Thanks, Jerry

Expert's answer

We have a combination of 7 cards from the deck. Total number of possible

variants is

52C7=52!/(52-7)!7!=133784560. And there is only 3 possible

variants for our situation (they differ by suit of a seven which is out). So the

probability is 3/133784560=0.00000224%

variants is

52C7=52!/(52-7)!7!=133784560. And there is only 3 possible

variants for our situation (they differ by suit of a seven which is out). So the

probability is 3/133784560=0.00000224%

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