Answer to Question #10149 in Other Math for judson9
Playing texas hold'em yesterday my Sweetie had a 7 and a queen in the pocket. On the board came up three sevens and two queens. Not a very likely mix. What is the likelihood of such a thing?
We have a combination of 7 cards from the deck. Total number of possible variants is 52C7=52!/(52-7)!7!=133784560. And there is only 3 possible variants for our situation (they differ by suit of a seven which is out). So the probability is 3/133784560=0.00000224%