# Answer to Question #2866 in Geometry for kyrsten black

Question #2866

The circle has diameter RS where R is (-3,2) and S is (3,2). Find the equation of the circle.

Expert's answer

Let's find the center of the circle, it lays on the middle of the interval RS and has the coordinates:

(3+(-3)/2, (2+2)/2)

O (0, 2).

The radius of this circle would be

R

R = 3.

Thus the equation of the circle is

x

(3+(-3)/2, (2+2)/2)

O (0, 2).

The radius of this circle would be

R

^{2}= (3-0)^{2}+ (2-2)^{2}= 9R = 3.

Thus the equation of the circle is

x

^{2}+ (y-2)^{2}= 9Need a fast expert's response?

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