Question #2695

A catheter of a triangle is 48 DM and the other is 3 / 4 of it.calcolate height measurement on the hypotenuse.

Expert's answer

If one catheter is 48 DM, another one would be 48*3/4 = 36 DM

The hypothenuse is equal to square root of the sum of squared catheters:

H = √(48^{2} + 36^{2}) = 60 DM.

The hypothenuse is equal to square root of the sum of squared catheters:

H = √(48

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