The three perpendicular distances of three sides of an equilateral triangle from a point which lies inside that triangle are 6 cm,9 cm and 12 cm respectively.The perimeter of the triangle is
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Expert's answer
2012-12-28T07:55:57-0500
Triangle ABC Point O H1- point of intersection with BC, OH1=12 H2 - point of intersection with AB, OH2=6 BH1=a angle OBH=å. 12=a*tgå 6/sinå=12/sin(60-å) (sine theorem) sin(60-å)/sinå=1/2 sin60coså-cos60sinå=1/2sinå Sqrt(3)/2=tgå a=24/sqrt(3) Analogically CH=b b=12/(2Sqrt(3)5)=30/Sqrt(3)) Side is equal to 54/sqrt(3) So, perimeter is 54sqrt(3)
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