Answer to Question #20243 in Geometry for Earl louie
N = 2[m]/1[cm] = 200[cm]/1[cm] = 200
times less then the original building. So, the hall of the length and breadth of 25m and 18m will be represented on the map by the area of
A = (25[m]/200)·(18[m]/200) = 0.01125[m²].
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