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Answer to Question #4194 in Calculus for John

Question #4194
Prove that integral(bottom=a, top=b) (x2+1)e-x^2& dx & >= & (e-a^2& - e-b^2)
Expert's answer
Denote x_1 = 1/2
x_2 = -1/4
x_3 = 1/8
x_4 = -1/16
Then
x1 = 1/2 = 1/(21) = (-1)1+1/(21)x2 = -1/4 = -1/(22) = (-1)2+1/(22)x3 = 1/8 = 1/(23) = (-1)3+1/(23)x4 = 1/16 = 1/(24) = (-1)4+1/(24)Thus the general formula for x_n is the following
xn = -1n+1/ 2n

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