# Answer to Question #4169 in Calculus for Terence

Question #4169

Determine the relative extrema of the function h = x

^{2}+ (y - 3)^{2}+ (z + 1)^{2}Expert's answer

relative extrema: dh/dx=2x=0

=> x=0 is extremum point

dh/dy=2(y-3)=0

=> y=3 is extremum point

dh/dz=2(z+1)=0

=> z=-1 is extremum point

Hence (0,3,-1) is the relative extrema point of this function

=> x=0 is extremum point

dh/dy=2(y-3)=0

=> y=3 is extremum point

dh/dz=2(z+1)=0

=> z=-1 is extremum point

Hence (0,3,-1) is the relative extrema point of this function

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