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Answer to Question #4169 in Calculus for Terence

Question #4169
Determine the relative extrema of the function h = x2 + (y - 3)2 + (z + 1)2
Expert's answer
relative extrema: dh/dx=2x=0
=> x=0 is extremum point
dh/dy=2(y-3)=0
=> y=3 is extremum point
dh/dz=2(z+1)=0
=> z=-1 is extremum point
Hence (0,3,-1) is the relative extrema point of this function

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