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Answer to Question #18609 in Calculus for M Asad

Question #18609
Find the equation for circle with center (1,3) that passes through (4, -1)
Expert's answer
The equation of the circle is (x-a)^2+(y-b)^2=r^2,
where (a,b) - coordinates of the centre and r - radius of the circle.
Then (4-1)^2+(-1-3)^2=r^2
25=r^2 then r=5
Finally the equation of the given circle is (x-1)^2+(y-3)^2=25

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Assignment Expert
19.11.12, 14:11

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Asad
18.11.12, 10:59

Thank you very very very very much Sir.

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