# Answer to Question #18281 in Calculus for arsslan

Question #18281

Find the equation for circle with center (1,3) that passes through (4, -1).

Expert's answer

The equation of the circle is (x-a)^2+(y-b)^2=r^2,

where (a,b) - coordinates of the centre and r - radius of the circle.

Then (4-1)^2+(-1-3)^2=r^2

25=r^2 then r=5

Finally the equation of the given circle is (x-1)^2+(y-3)^2=25

where (a,b) - coordinates of the centre and r - radius of the circle.

Then (4-1)^2+(-1-3)^2=r^2

25=r^2 then r=5

Finally the equation of the given circle is (x-1)^2+(y-3)^2=25

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