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Answer to Question #1702 in Calculus for Vaishu
Question #1702
Find dy/dx by implicit differentiation.
9sin(x) + cos(y) = sin(x) cos(y)
9sin(x) + cos(y) = sin(x) cos(y)
Expert's answer
F(x,y) = 9sin(x) +cos(y) - sin(x)cos(y) =0,
F'x = 9cos(x) - cos(x) cos(y);
F'y = -sin(y) + sin(x) sin(y);
dy/dx = -F'x / F'y = (9cos(x) - cos(x) cos(y)) / (sin(y) - sin(x) sin(y)).
F'x = 9cos(x) - cos(x) cos(y);
F'y = -sin(y) + sin(x) sin(y);
dy/dx = -F'x / F'y = (9cos(x) - cos(x) cos(y)) / (sin(y) - sin(x) sin(y)).
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