# Answer to Question #1702 in Calculus for Vaishu

Question #1702

Find dy/dx by implicit differentiation.

9sin(x) + cos(y) = sin(x) cos(y)

9sin(x) + cos(y) = sin(x) cos(y)

Expert's answer

F(x,y) = 9sin(x) +cos(y) - sin(x)cos(y) =0,

F'

F'

dy/dx = -F'

F'

_{x }= 9cos(x) - cos(x) cos(y);F'

_{y}= -sin(y) + sin(x) sin(y);dy/dx = -F'

_{x}/ F'_{y}= (9cos(x) - cos(x) cos(y)) / (sin(y) - sin(x) sin(y)).Need a fast expert's response?

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