# Answer to Question #13287 in Calculus for PRAMOD KUMAR

Question #13287

if a,b,c,d,e,f are non negative real numbers and a+b+c+d+e+f=1 then maximum value of ab+bc+cd+de+ef

Expert's answer

(a+b+c+d+e+f)^2=1

A^2+b^2+c^2+d^2+e^2+f^2+2(ab+bc+cd+de+ef) = 1

(ab+bc+cd+de+ef)<1/2

Ans 1/2

A^2+b^2+c^2+d^2+e^2+f^2+2(ab+bc+cd+de+ef) = 1

(ab+bc+cd+de+ef)<1/2

Ans 1/2

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