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Answer to Question #12637 in Calculus for Bryan Grasso

Question #12637
Log I = Log 10^-16 + 9....Im having trouble solving for I. I understand Log 10 to any power is that number (in this case, -16). But I still am having trouble solving for I
Expert's answer
Log I = Log 10^-16 + 9
As you've mentioned absolutely correctly, Log 10^-16=-16*Log 10=-16
Therefore we have Log I = Log 10^-16 + 9=-16+9=-8
So due to definition of logarithm I=10^-8

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