76 858
Assignments Done
Successfully Done
In June 2019

Answer to Question #12637 in Calculus for Bryan Grasso

Question #12637
Log I = Log 10^-16 + 9....Im having trouble solving for I. I understand Log 10 to any power is that number (in this case, -16). But I still am having trouble solving for I
Expert's answer
Log I = Log 10^-16 + 9
As you've mentioned absolutely correctly, Log 10^-16=-16*Log 10=-16
Therefore we have Log I = Log 10^-16 + 9=-16+9=-8
So due to definition of logarithm I=10^-8

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!


No comments. Be first!

Leave a comment

Ask Your question

Privacy policy Terms and Conditions