# Answer to Question #22637 in Algebra for ekra

Question #22637

If R is a ring with identity, then prove that

<a>l ={ ta ; tЄR } = Ra

<a>r ={ at ; tЄR } = aR

<a>={ ∑_finit^n▒sia t I ; si ,ti ЄR} = RaR

<a>l ={ ta ; tЄR } = Ra

<a>r ={ at ; tЄR } = aR

<a>={ ∑_finit^n▒sia t I ; si ,ti ЄR} = RaR

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