# Answer to Question #1698 in Algebra for Doug

Question #1698

A new cruise ship line has just launched 3 new ships. The Pacific Paradise, the Caribbean Paradise, & the Mediterranean Paradise. The Caribbean Paradise has 37 more deluxe staterooms than the Pacific Paradise. The Mediterranean Paradise has 40 fewer deluxe staterooms than 4 times the number of deluxe staterooms on the Pacific Paradise. Find the number of deluxe staterooms for each of the ship if the total number of deluxe staterooms for the 3 ships is 819.

Expert's answer

Denote the number of deluxe staterooms in Pacific Paradise as x,

as the Caribbean Paradise has 37 more deluxe staterooms than the Pacific Paradise, it would have (x+ 37) staterooms,

as the Mediterranean Paradise has 40 fewer deluxe staterooms than 4 times the number of deluxe staterooms on the Pacific Paradise, it would have (4x - 40) deluxe staterooms.

The total number of staterooms is:

x + x + 37 + 4x - 40 = 819

6x - 3 = 819

6x = 822

x = 137

x + 37 = 174

4x - 40 = 508

Thus the Pacific Paradise has 137 deluxe staterooms, the Caribbean Paradise has 174 deluxe staterooms, the Mediterranean Paradise has 508 deluxe staterooms.

as the Caribbean Paradise has 37 more deluxe staterooms than the Pacific Paradise, it would have (x+ 37) staterooms,

as the Mediterranean Paradise has 40 fewer deluxe staterooms than 4 times the number of deluxe staterooms on the Pacific Paradise, it would have (4x - 40) deluxe staterooms.

The total number of staterooms is:

x + x + 37 + 4x - 40 = 819

6x - 3 = 819

6x = 822

x = 137

x + 37 = 174

4x - 40 = 508

Thus the Pacific Paradise has 137 deluxe staterooms, the Caribbean Paradise has 174 deluxe staterooms, the Mediterranean Paradise has 508 deluxe staterooms.

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