Find three consecutive whole numbers such that twice the sum of the two smallest numbers is 18 more than three times the largest number.
______ (smallest value)
______ (largest value)
1
Expert's answer
2011-02-17T05:36:46-0500
Denote these three numbers as x, x+1 and x+2. The twice sum of two smallest numbers would be 2(x+(x+1)) = 18 + 3(x+2). Let's find the x: 2x+2x+2 = 18 + 3x + 6 x = 22 x+1 = 23 x+2 = 24 smallest value is 22; the largest value is 24
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment