# Answer to Question #13240 in Algebra for peter sassano

Question #13240

the sum of 3 consecutive even integers is 72. Find the 3 integers

Expert's answer

Let's denote the smallest integer as 2k, k-integer. Then another two are 2k+2, 2k+4.

So we obtain:

2k+(2k+2)+(2k+4)=72

6k+6=72

6k=66

k=11

Therefore required numbers are 22, 24,26

So we obtain:

2k+(2k+2)+(2k+4)=72

6k+6=72

6k=66

k=11

Therefore required numbers are 22, 24,26

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