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Answer to Question #13240 in Algebra for peter sassano
Question #13240
the sum of 3 consecutive even integers is 72. Find the 3 integers
Expert's answer
Let's denote the smallest integer as 2k, k-integer. Then another two are 2k+2, 2k+4.
So we obtain:
2k+(2k+2)+(2k+4)=72
6k+6=72
6k=66
k=11
Therefore required numbers are 22, 24,26
So we obtain:
2k+(2k+2)+(2k+4)=72
6k+6=72
6k=66
k=11
Therefore required numbers are 22, 24,26
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