# Answer on Algebra Question for peter sassano

Question #13240

the sum of 3 consecutive even integers is 72. Find the 3 integers

Expert's answer

Let's denote the smallest integer as 2k, k-integer. Then another two are 2k+2, 2k+4.

So we obtain:

2k+(2k+2)+(2k+4)=72

6k+6=72

6k=66

k=11

Therefore required numbers are 22, 24,26

So we obtain:

2k+(2k+2)+(2k+4)=72

6k+6=72

6k=66

k=11

Therefore required numbers are 22, 24,26

Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment