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Answer to Question #13209 in Algebra for Emily

Question #13209
3x√8x - 4√x^3 + 3x√72x ;X=2.
x≠-y 3x/1/x+y (3x is over 1 which is over x+y =?)
Expert's answer
3x*sqrt(8x) + 4*sqrt(x^3) + 3x*sqrt(72x) = 6x*sqrt(2x) + 4x*sqrt(x) + 6*3x*sqrt(2x) = 24x*sqrt(2x) + 4x*sqrt(x);

If x=2 the value of expression is 24*2*2 - 8*sqrt(2) = 96 - 8*sqrt(2)

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