# Answer to Question #13139 in Algebra for terry

Question #13139

water tower holds 1 million gallons at 37 ft in height, what percentage of water remains in the tower when the level drops to 26 ft?

Expert's answer

Water tower's volume is

V = πR²H,

where H and R are tower's height and radius respectively. So, the radius of a tower is

R = √(V/(πH)) = √(3.78541178*10^3*l/(3.14159265*37*0.3048m)) ≈ 10.3365 m.

If the level drops to 26 ft the volume of water remains

W = 3.14159265*(10.3365m)²*(26*0.3048m) ≈ 2660.0218 m³ ≈ 702703 gallons.

So, there remains

702703/10^6*100% ≈ 70%

of water.

V = πR²H,

where H and R are tower's height and radius respectively. So, the radius of a tower is

R = √(V/(πH)) = √(3.78541178*10^3*l/(3.14159265*37*0.3048m)) ≈ 10.3365 m.

If the level drops to 26 ft the volume of water remains

W = 3.14159265*(10.3365m)²*(26*0.3048m) ≈ 2660.0218 m³ ≈ 702703 gallons.

So, there remains

702703/10^6*100% ≈ 70%

of water.

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